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Math inequality.

Started by Dewo, February 08, 2012, 04:50:56 PM

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Dewo

February 08, 2012, 04:50:56 PM Last Edit: February 08, 2012, 04:53:35 PM by Dewo
(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)


Post the whole process.

X

antisickness

x^2 +8x+16+4x^2+8 > x^2-4x+4+4x^2+8
= 5x^2+8x+24 > 5x^2+12
= 8x > -12
= x > -12/8

may have made mistake cause writing in comp aint mah thing.

jura ples

5thnbg

Quote from: antisickness on February 08, 2012, 04:56:08 PM
x^2 +8x+16+4x^2+8 > x^2-4x+4+4x^2+8
= 5x^2+8x+24 > 5x^2+12
= 8x > -12
= x > -12/8

may have made mistake cause writing in comp aint mah thing.

jura ples
The final result its -3/2

mo9

2x+8+8x+8 > 2x-4+4x (to the power of 2 lol) + 8x
10x+16 > 10x +4x (to the power of 2) -4
16-4 > 10x-10x + 4x (to the power of 2)
12 > 4x (to the power of 2)
3> x squared
Square root 3 > x

sowwy if i did anything wrong

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antisickness

mayb i did something wrong along the way... cba getting my pen and paper out tho rofl

5thnbg

February 08, 2012, 05:58:28 PM #5 Last Edit: February 08, 2012, 06:05:42 PM by 5thnbg
Quote from: Dewo on February 08, 2012, 04:50:56 PM
(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)


Post the whole process.

(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)
x*2 + 8x + 16 + 4x*2 + 8 > x*2 - 4x +4 + 4x*2 + 8x
5x*2 + 8x + 24 > 5x*2 + 4x + 4
8x + 24 > 4x + 4
4x > -20
x > -5


P.S. : If there is something that we really do in the romanian schools...i can asure you thats math.

Dewo

Quote from: 5thnbg on February 08, 2012, 05:58:28 PM
Quote from: Dewo on February 08, 2012, 04:50:56 PM
(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)


Post the whole process.

(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)
x*2 + 8x + 16 + 4x*2 + 8 > x*2 - 4x +4 + 4x*2 + 8x
5x*2 + 8x + 24 > 5x*2 + 4x + 4
8x + 24 > 4x + 4
4x > -20
x > -5


P.S. : If there is something that we really do in the romanian schools...i can asure you thats math.
I hope, you are right.
Thanks to those who used some of their time to help me. I appreciate it.

X

5thnbg

Quote from: Dewo on February 08, 2012, 06:12:22 PM
Quote from: 5thnbg on February 08, 2012, 05:58:28 PM
Quote from: Dewo on February 08, 2012, 04:50:56 PM
(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)


Post the whole process.

(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)
x*2 + 8x + 16 + 4x*2 + 8 > x*2 - 4x +4 + 4x*2 + 8x
5x*2 + 8x + 24 > 5x*2 + 4x + 4
8x + 24 > 4x + 4
4x > -20
x > -5


P.S. : If there is something that we really do in the romanian schools...i can asure you thats math.
I hope, you are right.
Thanks to those who used some of their time to help me. I appreciate it.
Do the verification.. For example change x with -5 and then with -4...
Do i get jura or smthing?

Yz

**** uguys for helping dewo for free and not me for a jura+love

8====>heads
DISCORD killyzkill

mo9

ZeaL Rank 1 BvB, just because


vv secks box

Toast



Rossbach

February 08, 2012, 09:38:51 PM #11 Last Edit: February 08, 2012, 09:43:55 PM by Rossbach
(x + 4)*2 + 4(x*2 + 2) > (x - 2)*2 + 4x(x + 2)

(x+4)(x+4) + 4x^2 + 8 > (x - 2) (x-2) +4x^2 + 8x  <---- Do not forget the middle terms. (x + 4)*2 is not x^2 + 4^2.

x^2 + 4x + 4x + 16 + 4x^2 + 8 > x^2 - 2x - 2x + 4 + 4x^2 +8x

5x^2 + 8x + 24 > 5x^2 + 4x + 4


4x > -20

x > -5

or:

20 > -4x

-20 < 4x

-5 < x

^ Note the change in > to < for future.





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Pokeh

you guys could've gave me those links before i failed math

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